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What is the sum of the first eight terms of a geometric series whose first term is 3 and whose common ratio is[tex]1/2[/tex]?

Sagot :

gufeliz1965

Use the geometric series formula:

S_n = [a_1(1 - r^(n)]/(1 - r)

Let a_1 = 3

Let n = 8

Let r = 1/2

S_8 = [3(1 - (1/2)^8]/[(1 - (1/2)]

Simplify the right side using your calculator to find S_8, which is the sum of the first 8 terms.

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