Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Explore thousands of questions and answers from a knowledgeable community of experts on our user-friendly platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

A 3.6 g sample of iron (III) oxide reacts with sufficient aluminum to be entirely used up.
How much iron is produced?

Sagot :

dsdrajlin

Answer:

0.046 mol

Explanation:

Step 1: Write the balanced equation

Fe₂O₃ + 2 Al ⇒ 2 Fe + Al₂O₃

Step 2: Calculate the moles corresponding to 3.6 g of Fe₂O₃

The molar mass of Fe₂O₃ is 159.69 g/mol.

3.6 g × 1 mol/159.69 g = 0.023 mol

Step 3: Calculate the moles of Fe produced from 0.023 moles of Fe₂O₃

The molar ratio of Fe₂O₃ to Fe is 1:2.

0.023 mol  Fe₂O₃ × 2 mol Fe/1 mol Fe₂O₃ = 0.046 mol Fe

Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.