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How much heat is added if 0.5137g of water increases in temperature by 0.871 degrees C?

Sagot :

Answer:

1.87 J

Explanation:

q = c x m x (T2-T1)

c- specific heat of water (4.186 j/g.C)

q = 4.186 x 0.5137 x 0.871 = 1.87 J

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