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pls helpp!!
the angles of a quadrilateral are x°, (x+5)°, (2x-25)° and (x+10)°
find the value of x​

Sagot :

Given:

The angles of a quadrilateral are x°, (x+5)°, (2x-25)° and (x+10)°.

To find:

The value of x.

Solution:

We know that the sum of all interior angles of a quadrilateral is 360°. So,

[tex]x^\circ+(x+5)^\circ+(2x-25)^\circ+(x+10)^\circ=180^\circ[/tex]

[tex](5x-10)^\circ=180^\circ[/tex]

It can be written as

[tex](5x-10)=180[/tex]

[tex]5x=180+10[/tex]

[tex]5x=190[/tex]

Divide both sides by 5.

[tex]x=\dfrac{190}{5}[/tex]

[tex]x=38[/tex]

Therefore, the value of x is 38.

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