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Sagot :
Answer:
W = 1.11 N
Explanation:
Given that,
Mass of a table, m = 0.44 kg
It is pushed against an inclined surface with a 15 inclination angle.
We need to find the amount of the horizontal component of the weight. The horizontal component of weight is given by :
[tex]W=mg\sin\theta\\\\W=0.44\times 9.8\times \sin(15)\\\\W=1.11\ N[/tex]
So, the amount of the horizontal component of the weight is 1.11 N.
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