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Which parametric equations represent (x + 1)2 + (y – 3)2 = 16


PLEASE HELP WILL GIVE BRAINLIEST


x = 8cos(t) – 1 and y = 8sin(t) + 3
x = –cos(t) + 8 and y = 3sin(t) + 8
x = 4cos(t) – 1 and y = 4sin(t) + 3
x = –cos(t) + 4 and y = 3sin(t) + 4

Sagot :

Answer:

x = 4cos(t) – 1 and y = 4sin(t) + 3

Step-by-step explanation:

Equation of a circle:

The equation of a circle has the following format:

[tex](x - x_0)^2 + (y - y_0)^2 = r^2[/tex]

In which:

The centre is is [tex](x_0,y_0)[/tex] and r is the radius. The parametric equations are given by:

[tex]x(t) = r\cos{(t)} + x_0[/tex]

[tex]y(t) = r\sin{(t)} + y_0[/tex]

In this question:

[tex](x + 1)^2 + (y - 3)^2 = 4^2[/tex]

This means that the centre is [tex](-1,3)[/tex] and the radius is 4. So, the answer is:

x = 4cos(t) – 1 and y = 4sin(t) + 3

Answer:

see image below

Step-by-step explanation:

View image Arlett08
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