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2. The sum of 4 consecutive odd numbers is 56.
Find the greatest of the 4 numbers.

Sagot :

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Required consecutive odd numbers are 11 , 13 , 15 , 17 .

Step-by-step explanation:
Let the required consecutive odd numbers are 2a + 1 , 2a + 3 , 2a + 5 , 2a + 7.

According to the question :
= > sum of the given odd numbers = 56
= > ( 2a + 1 ) + ( 2a + 3 ) + ( 2a + 5 ) + ( 2a + 7 ) = 56
= > 2a + 1 + 2a + 3 + 2a + 5 + 2a + 7 = 56
= > 2a + 2a + 2a + 2a + 1 + 3 + 5 + 7 = 56
= > 8a + 16 = 56
= > 8a = 56 - 16
= > 8a = 40
= > a = 40 / 8
= > a = 5

Therefore the required consecutive odd numbers are :
2x + 1 = 2( 5 ) + 1 = 10 + 1 = 11
2x + 3 = 2( 5 ) + 3 = 10 + 3 = 13
2x + 5 = 2( 5 ) + 5 = 10 + 5 = 15
2x + 7 = 2( 5 ) + 7 = 10 + 7 = 17
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