Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

4/4 pts
***
---the system of simoultanious equation
X+2y+z=6
2x+y+2z=6
X+y+z=5​

Sagot :

xero099

Answer:

The system of equations has no solution.

Step-by-step explanation:

Let the following system of linear equations:

[tex]x +2\cdot y + z = 6[/tex] (1)

[tex]2\cdot x + y + 2\cdot z = 6[/tex] (2)

[tex]x + y + z = 5[/tex] (3)

Since the quantity of equations and variables are the same, there is only one solution to this system. First, we clear [tex]x[/tex] in (3):

[tex]x = 5 - y - z[/tex]

And make substitution both in (1) and (2):

[tex](5-y-z) +2\cdot y + z = 6[/tex]

[tex]2\cdot (5-y-z)+y+2\cdot z = 6[/tex]

[tex]y = 1[/tex] (4)

[tex]y = 4[/tex] (5)

Which lead to a contradiction, since [tex]4\ne 5[/tex]. Therefore, the system of linear equations has no solution.

We hope this was helpful. Please come back whenever you need more information or answers to your queries. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.