Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.
Sagot :
Answer:
The final temperature of the gas would need to be approximately 158.4 K
Explanation:
The details of the sample of nitrogen gas are;
The initial temperature of the nitrogen gas, T₁ = 22.7°C = 295.85 K
The initial volume occupied by the gas, V₁ = 12.2 L
The initial pressure of the gas, P₁ = 150.4 kPa
The final volume of the gas, V₂ = 9.7 L
The final pressure of the gas, P₂ = 101.3 kPa
Let 'T₂', represent the final temperature of the gas, by the ideal gas equation, we have;
[tex]\dfrac{P_1 \times V_1}{T_1} = \dfrac{P_2 \times V_2}{T_2}[/tex]
[tex]\therefore \ T_2 = \dfrac{P_2 \times V_2 \times T_1 }{P_1 \times V_1}[/tex]
Plugging in the values gives;
[tex]\therefore \ T_2 = \dfrac{101.3 \, kPa \times 9.7 \ L \times 295.85 K}{150.4 \ kPa \times 12.2 \ L} \approx 158.4327959 \ K[/tex]
The final temperature of the gas, T₂ ≈ 158.4 K
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.