Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Discover a wealth of knowledge from experts across different disciplines on our comprehensive Q&A platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
Answer:
The final temperature of the gas would need to be approximately 158.4 K
Explanation:
The details of the sample of nitrogen gas are;
The initial temperature of the nitrogen gas, T₁ = 22.7°C = 295.85 K
The initial volume occupied by the gas, V₁ = 12.2 L
The initial pressure of the gas, P₁ = 150.4 kPa
The final volume of the gas, V₂ = 9.7 L
The final pressure of the gas, P₂ = 101.3 kPa
Let 'T₂', represent the final temperature of the gas, by the ideal gas equation, we have;
[tex]\dfrac{P_1 \times V_1}{T_1} = \dfrac{P_2 \times V_2}{T_2}[/tex]
[tex]\therefore \ T_2 = \dfrac{P_2 \times V_2 \times T_1 }{P_1 \times V_1}[/tex]
Plugging in the values gives;
[tex]\therefore \ T_2 = \dfrac{101.3 \, kPa \times 9.7 \ L \times 295.85 K}{150.4 \ kPa \times 12.2 \ L} \approx 158.4327959 \ K[/tex]
The final temperature of the gas, T₂ ≈ 158.4 K
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.