nasley
Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Our platform provides a seamless experience for finding reliable answers from a knowledgeable network of professionals. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Change
2.215(1 and 5 are recurring/repeating decimals)
in form of​ a/b

Sagot :

aroojumair2005

Answer:

Answer:

2.215=2 43/200

Step-by-step explanation:

Showing the work

Rewrite the decimal number as a fraction with 1 in the denominator

2.215=2.215/1

Multiply to remove 3 decimal places. Here, you multiply top and bottom by 103 = 1000

2.215/1×1000/1000=2215/1000

Find the Greatest Common Factor (GCF) of 2215 and 1000, if it exists, and reduce the fraction by dividing both numerator and denominator by GCF = 5,

2215÷5/1000÷5=443/200

Simplify the improper fraction,

=2 43/200

In conclusion,

2.215=2 43/200

Answer:

[tex]\frac{731}{330}[/tex]

Step-by-step explanation:

We require 2 equations with the repeating numbers placed after the decimal point.

let x = 2.2151515... ( multiply both sides by 10 and 1000 )

10x = 22.1515.... → (1)

1000x = 2215.1515.... → (2)

Subtract (1) from (2) thus eliminating the repeating decimal

990x = 2193 ( divide both sides by 990 )

x = [tex]\frac{2193}{990}[/tex] = [tex]\frac{731}{330}[/tex]

Thus

2.2151515..... = [tex]\frac{731}{330}[/tex]

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.