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Find the equation that passes through (5,2) and (2, -4)

Sagot :

Answer:

equation 1st lies in 1st quadrant 5 = x and y= 2

as well as second one is lie on 4th quadrant

Answer:

y = 2x - 8

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate m using the slope formula

m = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

with (x₁, y₁ ) = (5, 2) and (x₂, y₂ ) = (2, - 4)

m = [tex]\frac{-4-2}{2-5}[/tex] = [tex]\frac{-6}{-3}[/tex] = 2 , then

y = 2x + c ← is the partial equation

To find c substitute any of the 2 points into the partial equation

Using (5, 2 ), then

2 = 10 + c ⇒ c = 2 - 10 = - 8

y = 2x - 8 ← equation of line