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Sagot :
Answer:
Explanation:
The important part about this problem is the acceleration, which you must find by using
F = ma,
where F is the force applied,
m is the mass,
and a is the acceleration.
F = ma
10.1 N = (12.3 kg)a
a = 0.8211 m/s^2
Now use the kinematics equations.
d = vot + (1/2)at^2
where d is the distance moved,
vo is the initial velocity (0),
a is the acceleration,
and t is the time.
d = vot + (1/2)at^2
d = (0 m/s)(2.5 s) + (1/2)(0.8211 m/s^2)(2.5 s)^2
d = 2.57 m
a. The acceleration of the cart, is 0.821 [tex]m/s^2[/tex].
b. The car moved a distance of 30.63 meters starting from rest.
Given the following data:
- Mass of shopping cart = 12.3 kg
- Force = 10.1 N
- Initial velocity, u = 0 m/s (since the cart is starting from rest).
- Time, t = 2.50 seconds.
a. To find the acceleration of the cart, we would apply Newton's Second Law of Motion:
Mathematically, Newton's Second Law of Motion is given by this formula;
[tex]Acceleration = \frac{Force}{Mass}[/tex]
Substituting the given values, we have;
[tex]Acceleration = \frac{10.1}{12.3}[/tex]
Acceleration = 0.821 [tex]m/s^2[/tex]
Therefore, the acceleration of the cart, is 0.821 [tex]m/s^2[/tex].
b. To find the distance covered by the shopping cart, we would use the second equation of motion.
Mathematically, the second equation of motion is given by the formula;
[tex]S = ut + \frac{1}{2} at^2[/tex]
Where:
- S is the distance covered.
- u is the initial velocity.
- a is the acceleration.
- t is the time measured in seconds.
Substituting the values into the formula, we have;
[tex]S = 0(2.5) + \frac{1}{2} (9.8)(2.5)^2\\\\S = 0 + 4.9(6.25)[/tex]
Distance, S = 30.63 meters.
Therefore, the car moved a distance of 30.63 meters starting from rest.
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