Looking for reliable answers? Westonci.ca is the ultimate Q&A platform where experts share their knowledge on various topics. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Answer:
If the perimeter = 300m
let the ratio be in x
a/q.
3x + 5x + 7x. = 300m
15x = 300
x = 300/15
x = 20
hence angles are
60 , 100 and 140
hope it helps
Answer:
A ≈ 1500[tex]\sqrt{3}[/tex] m²
Step-by-step explanation:
sum the parts of the ratio, 3 + 5 + 7 = 15 parts
Divide perimeter by 15 to find the value of one part of the ratio.
300 ÷ 15 = 20 m ← value of 1 part of the ratio , then
3 parts = 3 × 20 = 60 m
5 parts = 5 × 20 = 100 m
7 parts = 7 × 20 = 140 m
The 3 sides of the triangle are 60 m, 100 m , 140 m
To calculate the area (A) having all 3 sides use Hero's formula
A = [tex]\sqrt{s(s-a)(s-b)(s-c)}[/tex]
where s is the semiperimeter and a, b , c the sides of the triangle
s = 300 m ÷ 2 = 150 m
let a = 60, b = 100 and c = 140 , then
A = [tex]\sqrt{150(150-60)(150-100)(150-140)}[/tex]
= [tex]\sqrt{150(90)(50)(10)}[/tex]
= [tex]\sqrt{6750000}[/tex]
= [tex]\sqrt{10000}[/tex] × [tex]\sqrt{675}[/tex]
= 100 × [tex]\sqrt{25(27)}[/tex]
= 100 × 5[tex]\sqrt{27}[/tex]
= 500 × [tex]\sqrt{9(3)}[/tex]
= 500 × 3[tex]\sqrt{3}[/tex]
= 1500[tex]\sqrt{3}[/tex] m²
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.