Discover a world of knowledge at Westonci.ca, where experts and enthusiasts come together to answer your questions. Get immediate and reliable answers to your questions from a community of experienced professionals on our platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
Answer:
If the perimeter = 300m
let the ratio be in x
a/q.
3x + 5x + 7x. = 300m
15x = 300
x = 300/15
x = 20
hence angles are
60 , 100 and 140
hope it helps
Answer:
A ≈ 1500[tex]\sqrt{3}[/tex] m²
Step-by-step explanation:
sum the parts of the ratio, 3 + 5 + 7 = 15 parts
Divide perimeter by 15 to find the value of one part of the ratio.
300 ÷ 15 = 20 m ← value of 1 part of the ratio , then
3 parts = 3 × 20 = 60 m
5 parts = 5 × 20 = 100 m
7 parts = 7 × 20 = 140 m
The 3 sides of the triangle are 60 m, 100 m , 140 m
To calculate the area (A) having all 3 sides use Hero's formula
A = [tex]\sqrt{s(s-a)(s-b)(s-c)}[/tex]
where s is the semiperimeter and a, b , c the sides of the triangle
s = 300 m ÷ 2 = 150 m
let a = 60, b = 100 and c = 140 , then
A = [tex]\sqrt{150(150-60)(150-100)(150-140)}[/tex]
= [tex]\sqrt{150(90)(50)(10)}[/tex]
= [tex]\sqrt{6750000}[/tex]
= [tex]\sqrt{10000}[/tex] × [tex]\sqrt{675}[/tex]
= 100 × [tex]\sqrt{25(27)}[/tex]
= 100 × 5[tex]\sqrt{27}[/tex]
= 500 × [tex]\sqrt{9(3)}[/tex]
= 500 × 3[tex]\sqrt{3}[/tex]
= 1500[tex]\sqrt{3}[/tex] m²
Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.