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The perimeter of a triangle is 300 m . If its sides are in the ratio 3:5:7. Find the area of the triangle.

Plzz answer fast.

Sagot :

Answer:

If the perimeter = 300m

let the ratio be in x

a/q.

3x + 5x + 7x. = 300m

15x = 300

x = 300/15

x = 20

hence angles are

60 , 100 and 140

hope it helps

Answer:

A ≈ 1500[tex]\sqrt{3}[/tex] m²

Step-by-step explanation:

sum the parts of the ratio, 3 + 5 + 7 = 15 parts

Divide perimeter by 15 to find the value of one part of the ratio.

300 ÷ 15 = 20 m ← value of 1 part of the ratio , then

3 parts = 3 × 20 = 60 m

5 parts = 5 × 20 = 100 m

7 parts = 7 × 20 = 140 m

The 3 sides of the triangle are 60 m, 100 m , 140 m

To calculate the area (A) having all 3 sides use Hero's formula

A = [tex]\sqrt{s(s-a)(s-b)(s-c)}[/tex]

where s is the semiperimeter and a, b , c the sides of the triangle

s = 300 m ÷ 2 = 150 m

let a = 60, b = 100 and c = 140 , then

A = [tex]\sqrt{150(150-60)(150-100)(150-140)}[/tex]

   = [tex]\sqrt{150(90)(50)(10)}[/tex]

   = [tex]\sqrt{6750000}[/tex]

   = [tex]\sqrt{10000}[/tex] × [tex]\sqrt{675}[/tex]

   = 100 × [tex]\sqrt{25(27)}[/tex]

    = 100 × 5[tex]\sqrt{27}[/tex]    

    = 500 × [tex]\sqrt{9(3)}[/tex]

   = 500 × 3[tex]\sqrt{3}[/tex]

   = 1500[tex]\sqrt{3}[/tex] m²