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12ax² - (9a² - 8b²) x + (2a² + 5ab + 2b²) = 0 solve for x​

Sagot :

really226

Answer:

[tex]\sqrt{\frac{(8b^2-9a^2)^2}{576a^2}-\frac{2b^2+5ab+2a^2}{12a} } -\frac{8b^2-9a^2}{24a} \\\\or\\-\sqrt{\frac{(8b^2-9a^2)^2}{576a^2}-\frac{2b^2+5ab+2a^2}{12a} } -\frac{8b^2-9a^2}{24a}[/tex]

Step-by-step explanation:

The quadratic formula for

[tex]ax^2+bx+c=0[/tex]

the solution is: (-b±√(b²-4ac))/(2a)

The solution is:

[tex]\sqrt{\frac{(8b^2-9a^2)^2}{576a^2}-\frac{2b^2+5ab+2a^2}{12a} } -\frac{8b^2-9a^2}{24a} \\\\or\\-\sqrt{\frac{(8b^2-9a^2)^2}{576a^2}-\frac{2b^2+5ab+2a^2}{12a} } -\frac{8b^2-9a^2}{24a}[/tex]

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