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Answered

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I want to solve these mathematical equations
2t-✓2= 3t+✓2. Number 1
(-x+2✓3)(-3x-✓2) =0 number 2

Sagot :

bdvgtm

Answer:

which class you read now

Answer:

see explanation

Step-by-step explanation:

Given

2t - [tex]\sqrt{2}[/tex] = 3t + [tex]\sqrt{2}[/tex] ( add [tex]\sqrt{2}[/tex] to both sides )

2t = 3t + 2[tex]\sqrt{2}[/tex] ( subtract 3t from both sides )

- t = 2[tex]\sqrt{2}[/tex] ( multiply both sides by - 1 )

t = - 2[tex]\sqrt{2}[/tex]

-----------------------------------------------------------

Given

(- x + 2[tex]\sqrt{3}[/tex] )(- 3x - [tex]\sqrt{2}[/tex] ) = 0

Equate each factor to zero and solve for x

- x + 2[tex]\sqrt{3}[/tex] = 0 ( subtract 2[tex]\sqrt{3}[/tex] from both sides )

- x = - 2[tex]\sqrt{3}[/tex] ( multiply both sides by - 1 )

x = 2[tex]\sqrt{3}[/tex]

- 3x - [tex]\sqrt{2}[/tex] = 0 ( add [tex]\sqrt{2}[/tex] to both sides )

- 3x = [tex]\sqrt{2}[/tex] ( divide both sides by - 3 )

x = - [tex]\frac{\sqrt{2} }{3}[/tex]

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