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Kp for the reaction CO2(g) + C(s) --- 2CO(g) is 1.47 at 727°C. Calculate Kc at this temperature.

Sagot :

Cricetus

Answer:

The correct answer is "0.0179".

Explanation:

The given reaction is:

⇒ [tex]CO_2(g) + C(s) \rightleftharpoons 2 \ CO(g)[/tex]

The given value is:

At 727°C temperature,

Kp = 1.47

As we know,

Gas constant,

R = 0.0821 L atm/mol.K

Temperature,

= [tex]727+273[/tex]

= [tex]1000 \ K[/tex]

Now,

The change in moles will be:

⇒ [tex]\Delta n=Products-reactants[/tex]

⇒       [tex]=2-1[/tex]

⇒       [tex]=1[/tex]

As we know,

⇒  [tex]K_p=K_c(RT)^{\Delta n}[/tex]

On substituting the given values, we get

⇒  [tex]1.47=K_c(0.0821\times 1000)^1[/tex]

⇒    [tex]K_c=\frac{1.47}{0.0821\times 1000}[/tex]

⇒          [tex]=\frac{1.47}{82.1}[/tex]

⇒          [tex]=0.0179[/tex]

The correct answer is "0.0179".

Relationship between [tex]k_p[/tex] and [tex]k_c[/tex] is as follows:-

[tex]k_p=k_c(RT)^{n}[/tex]

At 727°C temperature,

Kp = 1.47

Gas constant,R = 0.0821 L atm/mol.K

Temperature=[tex]727+273=1000 K[/tex]

Now,

The change in moles will be:[tex]2-1=1[/tex]

On substituting the given values, we get

[tex]1.47=k_c\times(0.0821\times1000)^{1} \\\\k_c=0.0179[/tex]

To know more about:-

brainly.com/question/23276291

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