Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.

Mrs. B. invested ¢30,000; part at 5%, and part at 8%. The total interest on the
investment was $2,100. How much did she invest at each rate?
(Use semicolon to separate multiple answers)

Sagot :

Dana2022

Answer:

Let p be the amount invested at 8%. Then the amount invested at 5% would be 30,000-p. So:

.08p+.05(30,000-p)=2100

.03p+1500=2100

.03p=600

p=20,000

$20,000 was invested at 8%; $10,000 was invested at 5%

Step-by-step explanation:

IF RIGHT PLZ GIVE BRAINLIEST  

THANK U  

HAVE A GREAT DAY AND BE SAFE :)

XD

$20,000 was invested at 8% and $10,000 was invested at 5%

What is Algebra?

Algebra is the study of graphic formulas, while logic is the interpretation among those signs.

Mrs. B. invested ¢30,000; part at 5%, and part at 8%.

The total interest on the investment was $2,100.

Let p be the amount invested at 8%.

Then the amount invested at 5% would be 30,000 – p.

Then the equation will be

0.08p + 0.05(30000 – p) = 2100

On simplifying, we have

(0.08 – 0.05)p + 1500 = 2100

                         0.03p = 600

                                 p = $20,000

$20,000 was invested at 8% and $10,000 was invested at 5%

More about the Algebra link is given below.

https://brainly.com/question/953809

#SPJ2

We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.