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In ΔMNO, the measure of ∠O=90°, the measure of ∠M=11°, and NO = 80 feet. Find the length of OM to the nearest tenth of a foot. Please show work.

Sagot :

thebecks

Answer:

OM = 411.56 ft

Step-by-step explanation:

tan 11 = 80/x

0.1944 = 80/x

x = 411.56 ft

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