morakakgohu
Answered

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[tex]x - 1 = \sqrt{ \frac{y + 7}{2} } [/tex]
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Sagot :

Solving for x:

[tex]x = \sqrt{ \frac{y + 7}{2} } + 1[/tex]

Step-by-step explanation:

1) Just add 1 to both sides.

Solving for y:

[tex]y = 2( {x}^{2} - 2x + 1) - 7[/tex]

Step by step explanation:

1) Square both sides.

[tex] {x}^{2} - 2x + 1 = \frac{y + 7}{2} [/tex]

2) Multiply both sides by 2.

[tex]( {x}^{2} - 2x + 1) \times 2 = y + 7[/tex]

3) Regroup terms.

[tex]2( {x}^{2} - 2x + 1) = y + 7[/tex]

4) Subtract 7 from both sides.

[tex]2( {x}^{2} - 2x + 1) - 7 = y[/tex]

5) Switch sides.

[tex]y = 2( {x}^{2} - 2x + 1) - 7[/tex]

Therefor, the answer for Y is y = 2 ( x² - 2x + 1) -7.

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