Welcome to Westonci.ca, where your questions are met with accurate answers from a community of experts and enthusiasts. Ask your questions and receive accurate answers from professionals with extensive experience in various fields on our platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Consider this function f(x)=6log2x-3. Over which interval is function f increasing at the greatest rate?

Sagot :

Answer:

0 < x < 1.5..

Step-by-step explanation:

The derivative is 12/(2x - 3)

12/2x - 3 > 0

The interval is 0 < 2x < 3

That is 0 < x < 1.5..

The function f(x)=6log_2(x) - 3 increasing at the greatest rate in the interval [1/8, 1/2]

What are maxima and minima?

Maxima and minima of a function are the extrema within the range, in other words, the maximum value of a function at a certain point is called maxima and the minimum value of a function at a certain point is called minima.

We have a function:

[tex]\rm f(x) = 6log_2x-3\\[/tex]

For the interval x ∈[2, 6]

f(x) ∈ [-0.678, 3]

For the interval x ∈ [1/8, 1/2]

f(x) ∈ [ -9.96, -5.32]

For the interval x ∈ [1, 2]

f(x) ∈ [-3, -0.67]

For the interval x∈ [1/2, 1]

f(x) ∈ [-5.32, -3]

As we can see from the function value and its interval values the function increased at the greatest rate in the interval [1/8, 1/2]

Thus, the function f(x)=6log_2(x) - 3 increasing at the greatest rate in the interval [1/8, 1/2]

Know more about the maxima and minima here:

brainly.com/question/6422517

View image maheshpatelvVT