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Find the mean, variance, and standard deviation of the binomial distribution with the given values of n and p.
n = 80, p = 0.2


Sagot :

Answer:

mean =16

variance=12.8

standard deviation =3.578

Step-by-step explanation:

mean=np=80×0.2=16

variance= np(1-p)

=16(1-0.2)

=12.8

standard deviation =

[tex] \sqrt{12.8} [/tex]

=3.5777

=3.578