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Sagot :
Answer:21 moles of PbCl2 formed
Explanation: 3Pb(NO3)2(aq) + 2AlCl3(aq) --> 3PbCl2(s) + 2Al(NO3)3(aq)
14 moles AlCl3 x 3 moles PbCl2/2 moles AlCl3 =21 moles of PbCl2 formed
The number of moles of PbCl₂ produced when 14 moles of AlCl₃ are consumed in the reaction is 21 moles
Balanced equation
3Pb(NO₃)₂ + 2AlCl₃ —> 3PbCl₂ + 2Al(NO₃)₃
From the balanced equation above,
2 moles of AlCl₃ reacted to produce 3 moles of PbCl₂.
How to determine the mole of PbCl₂ produced
From the balanced equation above,
2 moles of AlCl₃ reacted to produce 3 moles of PbCl₂.
Therefore,
14 moles of AlCl₃ will react to produce = (14 × 3) / 2 = 21 moles of PbCl₂.
Thus, 21 moles of PbCl₂ were obtained from the reaction.
Learn more about stoichiometry:
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