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Sagot :
Answer:
See Explanation
Explanation:
8Fe + S₈ => 8FeS
Given: 10g 10g
moles 10g/56g/mol 10g/256g/mol
= 0.179mol Fe = 0.039mol S₈
Reduce => divide mole values by respective coefficients; smaller value is Limiting Reactant.
0.179/8 = 0.022 0.039/1 = 0.039
=> Fe is limiting reactant
8Fe + S₈ => 8FeS
Given: 10g/56g/mol 10g/256g/mol
= 0.179mol = 0.039 mol 0.179mol FeS produced
1/8(0.179)mol S₈ used (coefficients are equal,
= 0.022 mol S₈ used => moles Fe = moles FeS)
= (0.039 - 0.022)mol S₈ = 0.179mol FeS
remains in excess =(0.179mol)(88g/mol)
= 0.0166 mol S₈ (excess) = 15.8 g FeS
= (0.0166mol)(256g/mol) (Theoretical Yield)
= 4.26g S₈ in excess
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