Welcome to Westonci.ca, the Q&A platform where your questions are met with detailed answers from experienced experts. Experience the convenience of getting accurate answers to your questions from a dedicated community of professionals. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Solve the equation by completing the square. 0=x^2-14x+46 A. B. C. D.

Sagot :

Answer:

x = 16

Step-by-step explanation:

0=x^2-14x+46 is to be solved for x by completing the square.  The first two terms, x^2 and -14x, are the incomplete square.  We must find a term to add to, and then subtract from x^2 - 14x, so that we have a perfects square on the left and a negative number on the right:

x^2 - 14x = x^2 - 14x + (half of -14)^2 - (half of -14)^2 results in transformation of the original 0=x^2-14x+46 to

x^2 - 14x + 49 - 49 + 46 = 0, which simplifies to:

(x - 7)^2 - 3 = 0.  We want to solve this for x.

To do that, rewrite (x - 7)^2 - 3 = 0 as (x - 7)^2 = 3, and then square both sides.  We get:

x - 7 = 9, or x = 16

Answer:

x1=7-(square)3 x2=7+(square)3

Step-by-step explanation:

Swipe the sides of equation

Solve the quadratic equation ax^2+bx+c=0

Then using: x=((-)b+-(square)b^2-4ac):2a

Separate the solutions

Simplify