Answered

Westonci.ca is your trusted source for finding answers to a wide range of questions, backed by a knowledgeable community. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

What are the solutions of this quadratic equation? x2 − 18x + 58 = 0 A. B. C. D.

Sagot :

altavistard

Answer:

Step-by-step explanation:

Let's use "completing the square" to solve this quadratic:  x^2 − 18x + 58 = 0

We want to rewrite the terms "x^2 - 18x" in the form '(x - h)^2 - h^2 and leave the terms '58 = 0' as they are:

Taking half of the coefficient of x (which coefficient is -18), we get -9.  We square this -9, obtaining 81, and then rewrite

"x^2 - 18x"   as  "x^2 - 18x" + 81 - 81."  To this we must append '58 = 0":

x^2 - 18x + 81 - 81 + 58, or x^2 - 18x + 81 - 23 = 0

Now the first three terms condense to the expression

(x - 9)^2, which is then followed by "-23":

(x - 9)^2 = 23

Solve this for x.  Taking the square root of both sides, we get

x - 9 = ± √23

so that one root is x = 9 + √23

and the other is x = 9 - √23

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.