Answered

Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Get accurate and detailed answers to your questions from a dedicated community of experts on our Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

If 8.82 grams of Aluminum reacts, how many grams of AlCl3 will be produced?

Sagot :

Willchemistry

Hey there! :

Molar mass:

Al = 26.9815 g/mol

AlCl₃ = 133.3405 g/mol

Reaction stochemistry ,calculates the mass of AlCl3 produced

2 Al + 3 Cl₂ =  2 AlCl₃

2 * 26.9815 g Al ---------------------  2 *  133.3405 g AlCl₃

8.82 g Al -------------------------------  ( mass of AlC₃ )

mass of AlCl₃  =  ( 8.82 * 2 * 133.3405 ) /  ( 2 * 26.9815 )

mass of AlCl₃ = 2352.12642 / 53.963

mass of AlCl₃ = 43.58 g of AlCl₃

Hope this helps!

Thank you for visiting our platform. We hope you found the answers you were looking for. Come back anytime you need more information. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.