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a force of 500 Newton is used to stretch a spring with a 0.5 kg mass attached to it by 0.35 cm what is the value of the spring constant and frequency of the oscillator​

Sagot :

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Answer:

F. 20 cm m. The stretching force is the weight. (W = mg) of the 4 -kg mass: F = (4 kg)(9.8 m/s2) = 39.2 N.

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