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A ball is thrown up at a 60 degree angle and lands in 18.5 seconds. what is the initial velocity of the ball?

Sagot :

AyIin

Given :-

[tex] \sf \bullet \: \theta = {60}^{ \circ} [/tex]

[tex] \sf \bullet \:Time \: of \: flight , \: t = 18.5 \: s[/tex]

To Find :-

[tex] \bullet \sf \: Initial \: velocity , \: u[/tex]

Solution :-

[tex] \bf \star\boxed{ \bf t = \dfrac{2u \: sin \theta}{g} }[/tex]

[tex] : \implies \sf 18.5 = \dfrac{2u \: sin60}{10} [/tex]

[tex] : \implies \sf \: 2u \: sin60 = 185[/tex]

[tex]: \implies \sf u = \dfrac{185 \times 2}{ \sqrt{3} \times 2 } [/tex]

[tex]: \implies \sf u = \dfrac{185}{1.73} [/tex]

[tex] \bf: \implies u = 107 \: m {s}^{ - 1} [/tex]

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