Answer:
7) [tex]4 \ log_3(x) - 4 \ log_3(y)[/tex]
9) [tex]5log_4(7) - 5log_4(12)[/tex]
11) [tex]5log_5 \ (x) - log_5 \ (y)[/tex]
Step-by-step explanation:
[tex]log_3 (\frac{x}{y})^{4}[/tex]
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Use Logarithm of a Quotient which states
[tex]log_b \frac{M}{N} = log_b M-log_bN[/tex]
And also use Logarithm of a Power which states
[tex]log_b\ M^{n} = n\log_bM[/tex]
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So using these two properties,
7. [tex]4 \ log_3(x) - 4 \ log_3(y)[/tex]
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For #9, use the same logarithm propertied
[tex]log_4(\frac{7}{12})^5 = 5log_4(7) - 5log_4(12)[/tex]
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#11 is also the same concept
[tex]log_5\ \frac{x^5}{y} = 5log_5 \ (x) - log_5 \ (y)[/tex]
It is not - 5 log5(y) since only x is to the power of 5 not y
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Hope this is what you were looking for and helps you! Have a nice day/night :)
