Answered

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Find (x, y) for x and y are natural number such that
[tex] {2}^{x} + x = {y}^{2} [/tex]
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Sagot :

Answer:

(0,1),)(-1)

Step-by-step explanation:

[tex]y^2=2^x+x\\put x=0\\y^2=2^0+0=1+0=1\\y= \pm \sqrt{1} =\pm1[/tex]

so solutions are (0,1) and (0,-1)

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