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a chemical comapany makes two brands of antifreeze . the first brand is 70% pure antifreeze and the second is 95% pure antifreeze. In order to obtain 30 gallons of a mixture that contains 80% pure antifreeze how many gallons of each brand pf antifreeze must be uses

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Answer:hello mate

Step-by-step expla

12 gallons of 95% of antifreeze and 18 gallon of 70% of antifreeze for the mixture

What is Percentage?

In mathematics, a percentage is a number or ratio expressed as a fraction of 100.

What is Linear equation?

An equation between two variables that gives a straight line when plotted on a graph.

Given,

Quantity of pure antifreeze in first brand = 70%

Quantity of pure antifreeze in second brand = 95%

Consider,

x is the gallons in 95% pure antifreeze in the mixture

(30-x) is the gallon in 70% pure antifreeze in the mixture

We need to obtain 30 gallons of a mixture that contains 80% pure antifreeze.

Then the equation will become

0.95x + 0.70(30-x) = 0.8 × 30

0.95x-0.70x+21 =24

0.25x = 3

x = 12 gallons

There fore we need 12 gallons of 95% of antifreeze and 30-12 =18 gallon of 70% of antifreeze for the mixture.

Hence, 12 gallons of 95% of antifreeze and 18 gallon of 70% of antifreeze for the mixture

Learn more about Percentage and Linear equation here

https://brainly.com/question/22432227

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