Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Discover detailed solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

a 2.00x10^2 -g sample of water at 60 C is heated yo water vapor at 140 C. How much thermal energy is absorbed

Sagot :

Answer:

The thermal energy absorbed is 66.98 kJ.

Explanation:

The thermal energy absorbed can be found by using the following equation:

[tex] Q = mC\Delta T [/tex]

Where:

Q: is the thermal energy =?

m: is the mass of water = 2.00x10² g

ΔT = T₂ - T₁ = 140 °C - 60 °C = 80 °C

C: is the specific heat of water = 4.186 J/(°C*g)

Hence, the thermal energy absorbed is:  

[tex]Q = mC\Delta T = 2.00 \cdot 10^{2} g*4.186 \frac{J}{^{\circ} C*g}*80 ^{\circ} C = 66976 J = 66.98 kJ[/tex]

Therefore, the thermal energy absorbed is 66.98 kJ.

I hope it helps you!    

The thermal energy absorbed will be 66.98 kJ.heat loss is inverse to heat gain.

What are heat gain and heat loss?

Heat gain is defined as the amount of heat required to increase the temperature of a substance by some degree of Celcius.

Given data;

Q(thermal energy) =?

m(mass of water) = 2.00x10² g

C(specific heat of water) = 4.186 J/(°C*g)

ΔT = T₂ - T₁

ΔT = 140 °C - 60 °C

ΔT = 80 °C

It is given by the formula as ;

[tex]\rm Q= mcdt \\\\ Q= 2.00x10^2 \times 4.186 \times 80 \\\\ Q=66.98 \ kJ.[/tex]

Hence, the thermal energy absorbed will be 66.98 kJ.

To learn more about the heat gain refer to the link;

https://brainly.com/question/26268921

#SPJ5  

Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.