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If a 5 kg bowling ball is lifted to a height of 2 meters, how much potential
energy does it have?


Sagot :

Answer:

[tex]\boxed {\boxed {\sf 98.1 \ Joules}}[/tex]

Explanation:

The formula for potential energy is:

[tex]E_p=mgh[/tex]

where m is the mass, g is the gravitational acceleration, and h is the height.

The mass is 5 kilograms and the height is 2 meters. Assuming this ball is on Earth, then the gravitational acceleration is 9.81 meters per square second.

[tex]m= 5 \ kg \\g= 9.81 \ m/s^2 \\\h= 2 \ m[/tex]

Substitute the values into the formula.

[tex]E_p= ( 5 \ kg )(9.81 \ m/s^2)( 2 \ m)[/tex]

Multiply the first two numbers.

[tex]E_p=49.05 \ kg*m/s^2 (2 \ m )[/tex]

Multiply again.

[tex]E_p= 98.1 \ kg*m^2/s^2[/tex]

  • 1 kilogram square meter per square second is equal to 1 Joule.
  • Our answer is equal to 98.1 Joules

[tex]E_p= 98.1 \ J[/tex]

The ball has 98.1 Joules of potential energy.