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As indicated below, write the equations of the line passing through the point (2, 2) and perpendicular to the line whose equation is y = x.
Part 1: Point-Slope form of the linear equation

Part 2: Slope-intercept form of the linear equation

Part 3: The general form of the linear equation

Sagot :

abidemiokin

Answer:

See answers below

Step-by-step explanation:

Equation of a line in point slope form is expressed as;

y-y0 = m(x-x0)

m is the slope

(x0, y0) is a point on the line

Given the line y = x

The slope of the line is 1.

The slope of the line perpendicular is M = -1

Given the point (2,2)

x0 = 2 and y 0 = 2

Substitute

Recall y-y0 = m(x-x0)

y - 2 = -1(x-2) (Point slope form)

Express in slope intercept form;

y - 2 = -1(x-2)

Make y the subject of the formula;

y -2 = -x + 2

y = -x + 2 + 2

y = -x + 4 (slope intercept form)

The general form of linear equation is expressed as the slope intercept form which is y = -x+4

let y = f(x)

f(x) = -x+4

f(x) = 4-x (Linear equation)

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