The profit of the shopkeeper is $16.
Given that,
A shopkeeper buys 20kg of sugar at Birr y per kg.
He sells 16kgs at Birr (y+3/4) per kg and the rest at Birr (y+1) per kg.
We have to determine,
What is his profit?
According to the question,
The total quantity of sugar he buys is 20kg at y birr y kg.
Then the cost of sugar is,
[tex]\rm = 20 \times y\\\\= 20y[/tex]
And he sells 16kgs at Birr (y+3/4) per kg and the rest at Birr (y+1) per kg.
Then, the cost of sugar he sells is,
[tex]= \rm 16(y+\dfrac{3}{4})\\\\= 16y+ 16\times \dfrac{3}{4}\\\\= 16y + 12[/tex]
Left quantity of sugar = The total quantity of sugar - quantity of sugar he sells,
Left quantity of sugar = 20 kg - 16 kg
Left quantity of sugar = 4 kg
The rest of this at (y + 1) per kg will be,
[tex]\rm = 4 \times (y + 1) \\\\= 4y + 4[/tex]
The total selling price is thus;
[tex]\rm =4y + 4 + 16y + 12 \\\\= 20y + 16[/tex]
Therefore,
The profit is the difference between the selling and cost price is,
[tex]\rm = 20y + 16 - 20y\\\\= 16[/tex]
Hence, The required profit of the shopkeeper is $16.
For more details refer to the link given below.
https://brainly.com/question/17710675
