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find the direction angel of this vector <-5, 9>

Sagot :

Answer:

θ = -60.94°

Step-by-step explanation:

The given vector is:

v = -5i+9j

We need to find the angle of this vector.

The angle of this vector form is given by :

[tex]\tan\theta=\dfrac{y}{x}\\\\\tan\theta=\dfrac{9}{-5}\\\\\tan\theta=-1.8\\\\\theta=\tan^{-1}(-1.8)\\\\=-60.94^{\circ}[/tex]

So, the angle of this vector is -60.94°.