jhalamanisha4
Answered

At Westonci.ca, we make it easy to get the answers you need from a community of informed and experienced contributors. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

17. A train is travelling at a speed of 90 km/h.
Brakes are applied, so as to produce a
uniform acceleration of -0.5 m/s2. Find how
far the train will go before it is brought to rest?
Pg 110​

Sagot :

Answer:

x = 625 m

Explanation:

To solve this exercise we use the kinematics relations

          v² = v₀² - 2 a x

indicate that the train stops therefore its final speed is zero (v = 0)

           0 = v₀² - 2a x

           x = [tex]\frac{v_o^2}{2a}[/tex]

let's slow down to the SI system

           v₀ = 90 km / h (1000 m / 1km) (1h / 3600 s) = 25 m / s

let's calculate

           x = [tex]\frac{25^2}{2 \ 0.5}[/tex]

           x = 625 m

We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.