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a spring of original length 10 cm, Stretches to 12 cm, when a Force of 40 N is applied to It. what is the extension of the spring when a Force of 26 N, is applied?​

Sagot :

Answer:

2.6

Explanation:

Since the formula is k=F/X when you criscross it becomes KX=F,10X=26,then over ten which equals 2.6.

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