Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Discover comprehensive solutions to your questions from a wide network of experts on our user-friendly platform. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals.

Triangle ABC is a right-
angled triangle.
ADB is a straight line.
DA = DC
Angle BCD = 20°
Work out the size of the angle
marked x.
You must give reasons for each
stage of your working out


Triangle ABC Is A Right Angled Triangle ADB Is A Straight Line DA DC Angle BCD 20 Work Out The Size Of The Angle Marked X You Must Give Reasons For Each Stage O class=

Sagot :

Answer:

x=35°

Step-by-step explanation:

∠A+∠B+∠C=180°(ASP)

In ΔCAD, DC=DA

so, ∠DAC=∠DCA( angles opposite to equal sides are equal)

∠B=90°(given)

So, ∠DCA= 180°-(90+20)= 70°

Since ∠DCA= ∠DAC,

2x= 70°

x=35°

The value of angle A or the value of x is 35°

What is the triangle?

Triangle is a shape made of three sides in a two-dimensional plane. the sum of the three angles is 180 degrees.

The angle A will be calculated as:-

∠A+∠B+∠C=180°(ASP)

In ΔCAD, DC=DA

so, ∠DAC=∠DCA( angles opposite to equal sides are equal)

∠B=90°(given)

So, ∠DCA= 180°-(90+20)= 70°

Since ∠DCA= ∠DAC,

2x= 70°

x=35°

Therefore the value of angle A or the value of x is 35°

To know more about triangles follow

https://brainly.com/question/17335144

#SPJ2