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Given the equation Ca + H2O --> Ca(OH)2 + H2 how many grams of calcium will react completely with 10.0 grams of water? *

Sagot :

Answer: 11.0 g of calcium will react with 10.0 grams of water.

Explanation:

To calculate the moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}[/tex]

moles of [tex]H_2O[/tex]

[tex]\text{Number of moles}=\frac{10.0g}{18g/mol}=0.55moles[/tex]

The balanced chemical equation is:

[tex]Ca+2H_2O\rightarrow Ca(OH)_2+H_2[/tex]

According to stoichiometry :

2 moles of [tex]H_2O[/tex] require = 1 mole of [tex]Ca[/tex]

Thus 0.55 moles of [tex]H_2O[/tex] require=[tex]\frac{1}{2}\times 0.55=0.275moles[/tex]  of [tex]Ca[/tex]  

Mass of [tex]Ca=moles\times {\text {Molar mass}}=0.275moles\times 40g/mol=11g[/tex]

Thus 11.0 g of calcium will react with 10.0 grams of water.

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