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Two 31-m long parallel wires are 0.155 m apart. Each carries 168 A of current. What is the magnitude of the force between the wires? Please give your answer in Newtons.

Sagot :

onyebuchinnaji

Answer:

The magnitude of magnetic force between the two parallel wires is 1.13 N.

Explanation:

Given;

length of each wire, l = 31 m

distance between the two parallel wires, r = 0.155 m

current on each wire, I = 168 A

The magnitude of magnetic force between the two parallel wires is calculated as;

[tex]F = \frac{\mu _oI_1I_2 L}{2\pi r} \\\\F = \frac{(4\pi \times 10^{-7}) \times (168)^2 \times (31)}{2\pi \times 0.155} \\\\F = 1.13 \ N[/tex]

Therefore, the magnitude of magnetic force between the two parallel wires is 1.13 N.

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