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What is the coefficient of m in the sum of (23m−34)( 3 2 ​ m− 4 3 ​ ) and (−16m−r)(− 6 1 ​ m−r) ?

Sagot :

temdan2001

Answer:

77r - 2077

Step-by-step explanation:

To find the the sum of (23m−34)( 3 2 ​ m− 4 3 ​ ) and (−16m−r)(− 6 1 ​ m−r)

First open the bracket

23m × 32m - 23m × 43 - 34 × 32m + 34 × 43

736m^2 - 989m - 1088m + 1462

736m^2 - 2077m + 1462

Open the second bracket

16m × 61m + 16m × r + r × 61m + r × r

976m^2 + 16mr + 61mr + r^2

976m^2 + 77mr + r^2

Adding both equations together

736m^2 - 2077m + 1462 + 976m^2 + 77mr + r^2

1712m^2 + 77mr - 2077m + 1462 + r^2

1712m^2 + m( 77r - 2077 ) + 1462 + r^2

Therefore The coefficient of m is 77r - 2077

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