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Sagot :
Answer:
Two transformations or series of transformation that support Maria's claim and Maps ΔABE to ΔACD are;
A dilation with a scale factor of 3 about point A
A dilation with a scale factor of 3 about point B followed by a translation of 4 units downwards
Step-by-step explanation:
Using an online source, we have;
ΔABE ~ ΔACD
The coordinate of triangle ΔABC are;
A(-6, 4), B(-6, 2), and E(-2, 2)
The coordinate of triangle ΔACD are;
A(-6, 4), C(-6, -2), and D(6, -2)
∠A ≅ ∠A by reflexive property
Segment BE ║Segment CD and segment DE and segment AE are collinear on transversal AD
∴ ∠E ≅ ∠D Corresponding angles
∴ ΔABE ~ ΔACD by Angle-Angle rule of congruency
Segment AB on ΔABE and segment AC on triangle ΔACD are corresponding sides on both triangles
The length of segment AB on ΔABE = 2 units
The length of segment AC on ΔACD = 6 units
The scale factor of dilation, SF = (The length of segment AC)/(The length of segment AB)
∴ SF = (6 units)/(2 units) = 3
Therefore, ΔABE maps to ΔACD by either of the following;
1) A dilation with a scale factor of 3 about point A
2) A dilation with a scale factor of 3 about point B followed by a translation of 4 units downwards.
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