Answer:
The resulting pressure is 300 kilopascals.
Explanation:
Let consider that gas within the closed vessel behaves ideally. By the equation of state for ideal gases, we construct the following relationship for the isothermal relationship:
[tex]P_{1}\cdot V_{1} = P_{2} \cdot V_{2}[/tex] (1)
Where:
[tex]P_{1}[/tex], [tex]P_{2}[/tex] - Initial and final pressure, measured in kilopascals.
[tex]V_{1}[/tex], [tex]V_{2}[/tex] - Initial and final volume, measured in litres.
If we know that [tex]\frac{V_{1}}{V_{2}} = 2[/tex] and [tex]P_{1} = 150\,kPa[/tex], then the resulting pressure is:
[tex]P_{2} = P_{1}\times \frac{V_{1}}{V_{2}}[/tex]
[tex]P_{2} = 300\,kPa[/tex]
The resulting pressure is 300 kilopascals.
