Answered

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XYZ is a triangle in which XY = 11 centimeters and YZ = 15 centimeters. The length of XZ is in whole centimeters and is greater than 20 centimeters. What are the possible lengths of XZ?

Sagot :

Answer:

Possible lengths of [tex]XZ[/tex] are [tex]21\,\,cm,22\,\,cm,23\,\,cm,24\,\,cm,25\,\,cm[/tex]

Step-by-step explanation:

According to triangle inequality theorem,

length of one side is less than the sum of remaining two sides.

Also,

[tex]XY=11\,\,cm\\YZ=15\,\,cm\\XZ>20\,\,cm[/tex]

Therefore,

[tex]20<XZ<15+11\\20<XZ<26[/tex]

The length of [tex]XZ[/tex] is in whole centimeters.

Therefore, possible lengths of [tex]XZ[/tex] are [tex]21\,\,cm,22\,\,cm,23\,\,cm,24\,\,cm,25\,\,cm[/tex]

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