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How many cubes with side lengths of \dfrac13\text{ cm} 3 1 ​ cmstart fraction, 1, divided by, 3, end fraction, start text, space, c, m, end text does it take to fill the prism?

Sagot :

Answer:

48 cubes

Explanation:

Given

Cube

[tex]Side\ Length = \frac{1}{3}cm[/tex]

Prism [Missing from the question]

[tex]Length = 1cm[/tex]

[tex]Width= 2\frac{2}{3}cm[/tex]

[tex]Height = \frac{2}{3}cm[/tex]

Required

Determine the number of cubes the prism can take

Volume is calculated as:

[tex]V = Length * Width * Height[/tex]

First, calculate the volume of the cube

[tex]V_1 = \frac{1}{3} * \frac{1}{3} * \frac{1}{3} cm^3[/tex]

[tex]V_1 = \frac{1}{27} cm^3[/tex]

Next, calculate the volume of the prism

[tex]V_2 = 1 * 2\frac{2}{3} * \frac{2}{3}\ cm^3[/tex]

Convert to improper fraction

[tex]V_2 = 1 * \frac{8}{3} * \frac{2}{3}\ cm^3[/tex]

[tex]V_2 = \frac{16}{9}\ cm^3[/tex]

Divide V2 by V1 to get the number of cubes

[tex]Number = \frac{V_2}{V_1}[/tex]

[tex]Number = \frac{16}{9}/\frac{1}{27}[/tex]

[tex]Number = \frac{16}{9}*\frac{27}{1}[/tex]

[tex]Number = \frac{16*27}{9*1}[/tex]

[tex]Number = \frac{432}{9}[/tex]

[tex]Number = 48[/tex]

Hence, 48 cubes will fill the prism

Answer: 48 cubes.

Explanation:

V=H*L*W

3*8*2

This equals 48.

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