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Sagot :
Answer:
0.9783 = 97.83% probability that a can that gets shipped for use will be of perfect shape
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Shipped for use
Event B: Perfect shape
Probability of being shipped for use:
Perfect shape(0.9 probability) or unnoticeable dent(0.02 probability). So
[tex]P(A) = 0.9 + 0.02 = 0.92[/tex]
Being shipped for use and being in perfect shape.
0.9 probability, so [tex]P(A \cap B) = 0.9[/tex]
What is the probability that a can that gets shipped for use will be of perfect shape?
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.9}{0.92} = 0.9783[/tex]
0.9783 = 97.83% probability that a can that gets shipped for use will be of perfect shape
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