Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.
Sagot :
Answer:
0.9783 = 97.83% probability that a can that gets shipped for use will be of perfect shape
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Shipped for use
Event B: Perfect shape
Probability of being shipped for use:
Perfect shape(0.9 probability) or unnoticeable dent(0.02 probability). So
[tex]P(A) = 0.9 + 0.02 = 0.92[/tex]
Being shipped for use and being in perfect shape.
0.9 probability, so [tex]P(A \cap B) = 0.9[/tex]
What is the probability that a can that gets shipped for use will be of perfect shape?
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.9}{0.92} = 0.9783[/tex]
0.9783 = 97.83% probability that a can that gets shipped for use will be of perfect shape
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.
