At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Connect with a community of experts ready to provide precise solutions to your questions quickly and accurately. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
Answer:
0.9783 = 97.83% probability that a can that gets shipped for use will be of perfect shape
Step-by-step explanation:
Conditional Probability
We use the conditional probability formula to solve this question. It is
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)}[/tex]
In which
P(B|A) is the probability of event B happening, given that A happened.
[tex]P(A \cap B)[/tex] is the probability of both A and B happening.
P(A) is the probability of A happening.
In this question:
Event A: Shipped for use
Event B: Perfect shape
Probability of being shipped for use:
Perfect shape(0.9 probability) or unnoticeable dent(0.02 probability). So
[tex]P(A) = 0.9 + 0.02 = 0.92[/tex]
Being shipped for use and being in perfect shape.
0.9 probability, so [tex]P(A \cap B) = 0.9[/tex]
What is the probability that a can that gets shipped for use will be of perfect shape?
[tex]P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.9}{0.92} = 0.9783[/tex]
0.9783 = 97.83% probability that a can that gets shipped for use will be of perfect shape
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.
