Answered

Discover the answers you need at Westonci.ca, where experts provide clear and concise information on various topics. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

philip has 11 coins that equal a total of 82 cents. His coins include at least 1 quarter 1 dime 1 nickel and 1 penny. how many of each coin does he have

Sagot :

francocanacari

Answer:

Philip has 1 Quarter, 3 Dimes, 5 Nickels, and 2 Pennys.

Step-by-step explanation:

Given that Philip has 11 coins that equal a total of 82 cents, and his coins include at least 1 quarter 1 dime 1 nickel and 1 penny, to determine how many of each coin does he have the following calculation must be performed:

Quarter = 0.25

Dime = 0.10

Nickel = 0.05

Penny = 0.01

0.82 - 0.25 - 0.10 - 0.05 - 0.01 = 0.41

0.41 = 0.10 x 4 + 0.1 (5 coins + 4 previous coins = 9 coins).

0.41 = 0.10 x 2 + 0.05 x 4 + 0.01 (7 coins + 4 previous coins = 11 coins).

0.25 + (3 x 0.1) + (5 x 0.05) + (2 x 0.01) = X

0.25 + 0.30 + 0.25 + 0.02 = X

0.82 = X

Thus, Philip has 1 Quarter, 3 Dimes, 5 Nickels, and 2 Pennys.

Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is your go-to source for reliable answers. Return soon for more expert insights.