Answered

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At a certain conference the information technology session and the social media session occur at the same time so it is impossible for an attendee to sit in on both sessions. If the probability that an attendee sits in on the information technology session is 0.11, and the probability that an attendee sits in on the social media session is 0.62, what is the probability that an attendee sits in on the information technology session or the social media session?

Sagot :

Answer:

0.73 = 73% probability that an attendee sits in on the information technology session or the social media session.

Step-by-step explanation:

What is the probability that an attendee sits in on the information technology session or the social media session?

They cant be in both sections simultaneously, so this probability is the sum of each probability.

0.11 = 11% probability that an attendee sits in on the information technology session

0.62 = 62% probability that an attendee sits in on the social media session

0.11 + 0.62 = 0.73

0.73 = 73% probability that an attendee sits in on the information technology session or the social media session.

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