Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Experience the ease of finding accurate answers to your questions from a knowledgeable community of professionals. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
Answer:
(a) The algorithm is as follows:
count = 0
for i = 1 to n:
if x = xi:
count++
print(count)
(b) n comparisons
Explanation:
Solving (a):
Assume the integer to locate is x and the elements of the list are: [tex]x_1, x_2, x_3, x_4..... x_n[/tex]
Such that: [tex]x_1 \ge x_2 \ge x_3 ...... \ge x_n[/tex]
The algorithm is as follows:
count = 0
for i = 1 to n:
if x = xi:
count++
print(count)
The above iterates through the count of the list (i.e. n) and makes comparison with each element of the list (i.e. element 1 to element n).
When a match is found, the count variable is incremented by 1 and printed at the end of the loop
Furthermore:
If there are 3 elements in the list, the algorithm makes 3 comparisons.
It makes 10 comparisons if there are 10 elements in the list.
So: it makes n elements if there are n elements in the list
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're here to help at Westonci.ca. Keep visiting for the best answers to your questions.